Step 1: **2 x [ 3x^{2} - 20x + 28 ]**
Factor out anything common to all terms.

Step 2: **2 x [ 3x^{2} + (-20)x + 28 ]**
Write trinomial in standard form

Step 3: **2 x [ 3x^{2} + (-20)x + 28 ]**
Determine product of

Step 4: List all pairs of `a·c` If `a·c` is negative, then factors have opposite signs.

If `a·c` is positive, then factors have same signs. Sign of `b` determines sign of factors.

Factors of 84 are: ** -1, -84 -4, -21 -6, -14 -7, -12**

Select factor pair such that their sum is `b` term = -20

Step 5: Split middle term `b` order factors as multiple of the `a` and `c` terms
**2 x [3x^{2} + (-6)x + (-14)x + 28 ] **

Step 6: Factor out something common to first two terms.
**2 x [ 3x^{2} + (-6)x + (-14)x + 28 ] → 2x
[ 3 x(x-2) + (-14)x + 28 ]**

Step 7: Factor out same binomial in last two terms.
**2 x [ 3 x(x-2) + (-14)(x-2) ]**

Step 8: Apply Distributive Law and convert trinomial into the product of two binomials and a monomial.
**2 x [ (3x - 14)(x - 2) ] → 2x(3x - 14)(x - 2)**
This is the answer